this post was submitted on 01 May 2025
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Python

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There is an issue with the program when the user correctly guesses the number. The program should end when the break statement executes in the while loop found in main(), but instead it times out.

import random


def main():
    level = get_level()
    number = generate_random_number(level)

    while True:
        guess = get_guess()

        if check_guess(number, guess) == False:
            continue
        else:
            break


def get_level():
    while True:
        level = input("Level: ")

        try:
            int(level)
        except ValueError:
            continue
        if int(level) <= 0:
            continue
        else:
            return int(level)

def generate_random_number(level):
    number = random.randint(1, level)

    return number

def get_guess():
    while True:
        guess = input("Guess: ")

        try:
            int(guess)
        except ValueError:
            continue
        if int(guess) <= 0:
            continue
        else:
            return int(guess)

def check_guess(number, guess):
    if guess > number:
        print("Too large!")

        return False
    if guess < number:
        print("Too small!")

        return False
    if guess == number:
        print("Just right!")

        return True


main()
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[–] gedhrel@lemmy.world 0 points 1 year ago (2 children)

How is that checker configured?

It might be doing something like this:

import student_module
student_module.main()

and because you're already invoking main as the module is imported, it's getting stuck the second time around. Maybe add some indicative print at the entrypoint to your main function.

Another reply in here has supplied the standard idiom for making a module executable:

if __name__ == "__main__":
  main()
[–] milon@lemm.ee 0 points 1 year ago

The idiom allowed it to pass the checker's tests! Thanks for your help!

[–] logging_strict@programming.dev 0 points 1 year ago* (last edited 1 year ago) (1 children)

What duh eh does standard idiom mean?

In computer programming, a programming idiom, code idiom or simply idiom is a code fragment having a semantic role[1] which recurs frequently across software projects. It often expresses a special feature of a recurring construct in one or more programming languages, frameworks or libraries. This definition is rooted in the linguistic definition of "idiom".

https://en.wikipedia.org/wiki/Programming_idiom

So this term is vague and abstract. Really not a specific term or grouping of related things.

The actual terminology

That standard idiom is called, process guard or simply guard. Learn about this term when doing anything involving multiprocessing.

The if __name__ == "__main__": guard is important when working with multiprocessing in Python. This prevents the creation of duplicate processes when the module is imported.

https://labex.io/tutorials/python-how-to-pass-arguments-in-python-multiprocessing-430780

So it's totally not for what its being described as. Or that's an oversimplification with a loss of vital details of it's actual purpose.

It could be worse

When don't know the name for something, Call it stuff!. Ya know, when really suack at naming things, be unrepentant! Stuff is as bad of a term i could come up with. Means didn't know how to describe it to accurately relate what it is or does, without being vulgar; out of fear the typos author left an Easter egg which is best left lie.

Used this term once, for a SQLAlchemy non-request based router implementation, the Session (term already taken) i call SessionStuff. Doesn't that just scream competence and authoritative implementation?

What do you do for a job? Urrrh ... stuff?

Regretted immediately and still do. Cuz session seems to have three different contexts / meanings.

Oh shit! Used the term, stuff. That's code prefer to not even read. That's a thing of nightmares that haunts our collective waking moments.

[–] gedhrel@lemmy.world 0 points 1 year ago

You sound angry. Take a breath and grow up.